Description:
Mathematical discussions and pursuits.
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exr - quotient of infinite cyclic group
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I need to prove that if G=<x> is infinite and 1<H<=G, then |G:H| is finite. I'd like to show it using the fact that H=<x^k> for some positive integer k, then using the prime factorization theorem, we know that the possible supergroups of H are, in number, finite. Hence, by correspondence theorem,... more »
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A question in group theory
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Hi all: In anoother maths forum a question came up as follows: if H,K are two isomorphic subgroups of some group G, is there a group M in which G is embeddable s.t. the isomorphism between H,K is an inner one in M? There's a partial answer here: the holomorph of G, Hol(G), works if we know that an isomorphism between H,K... more »
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Trade Company - www.ec21i.com
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The sale of world famous jacket,Jean-COOGI/DG/gino green global /G- Star and so on Nike Air Jordan 1 I Force 1 Jordan Fusion AJF 1 AJF1 AJ1F Jordan 1 fusion [link] Nike Air Jordan 2 II Force 1 Jordan Fusion AJF 2 AJF2 AJ2F Jordan 2 fusion Nike Air Jordan 3 III Force 1 Jordan Fusion AJF 3 AJF3 AJ3F... more »
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Rationalize
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How to Rationalize the Denominator (1)1/(69 + Sqrt[3]) (2)1/(7 + 5^(1/3) + 3^(1/5)) (3)1/(7 + 5^(1/3) + 3^(1/5) + 2^(1/7))
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prove -1/2 is not a subsequential limit of S_n
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Here is the problem... S_n = -1 + (n+1)/2 cos((pi*n)/2) prove -1 is not a subsequential limit of S_n I am not sure where to start. Is it enough to consider various values for n and then show that of the resulting subsequences -1/2 is not a limit of any of them? That seems a little weird to me since we are not proving that we are... more »
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